8th Class Mathematics Mensuration Question Bank Mensuration

  • question_answer
    How many bricks of size \[\text{22 cm}\times \text{10 cm}\times \text{7 cm}\] are required to construct a wall 11m long, 3.5 m high and 40 cm thick, if the cement and sand used in the construction occupy \[{{\text{(1/10)}}^{\text{th}}}\] part of the wall?

    A)  8000  

    B)         9000  

    C)  7000  

    D)         10000

    Correct Answer: B

    Solution :

    Volume of a brick\[=(22\times 10\times 7)c{{m}^{3}}\]                                     \[=1540c{{m}^{3}}\] Now, length of the wall \[\text{=11 m - 1100 cm}\] Height of the wall \[\text{= 3}\text{.5 m = 350 cm}\] Width of the wall \[=\text{ }40\text{ }cm\] \[\therefore \] Volume of the wall \[=(1100\times 350\times 40)c{{m}^{2}}\] \[=15400000c{{m}^{3}}\] It is given that cement and sand occupy \[\frac{1}{10}th\] part of 15400000, i.e., \[1540000\text{ }c{{m}^{3}}\] Volume of the wall occupied by the bricks \[=\text{ }15400000-1540000=13880000\] \[\therefore \]Number of bricks \[\text{=}\frac{\text{volume of wall in which bricks are occupied}}{\text{volume of a brick}}\] \[\text{=}\frac{13860000}{1540}=9000\] Hence, 9000 bricks are required to construct the wall.


You need to login to perform this action.
You will be redirected in 3 sec spinner