A) 2.5 m
B) 12.5 m
C) 1.25m
D) 1.5m
Correct Answer: C
Solution :
Let r and h be the radius and depth of well. Volume of earth dug out \[=\pi {{r}^{2}}h\] \[=\frac{22}{7}\times \frac{3.5}{2}\times \frac{3.5}{2}\times 12=115.5{{m}^{2}}\] Let \[x\] be the height of platform Now, volume of platform =volume of earth dug not \[\Rightarrow 10.5\times 8.8\times x=115.5\] \[\Rightarrow x=\frac{115.5}{10.5\times 8.8}=1.25m\]
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