A) 3 : 2
B) 4 : 1
C) 3 : 1
D) 4 : 3
Correct Answer: B
Solution :
Let side of one square be \[x\] \[\therefore \]Area \[=\text{ }{{x}^{2}}\]. Now, its diagonal \[=\sqrt{2}\times x\] So, diagonal of other square\[=2\times \sqrt{2}x=2\sqrt{2}x\] Now, required side of other square \[=\text{ }2x\] \[\therefore \] Area \[={{(2x)}^{2}}\text{ }=\text{ }4{{x}^{2}}\] So, required ratio \[=\frac{4{{x}^{2}}}{{{x}^{2}}}=\frac{4}{1}i.e.,4:1\].
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