A) 200.53 \[c{{m}^{2}}\]
B) 220.53 \[c{{m}^{2}}\]
C) 240.8 \[c{{m}^{2}}\]
D) 250.8 \[c{{m}^{2}}\]
Correct Answer: D
Solution :
(d): \[\pi rl=\pi r\sqrt{{{r}^{2}}+{{h}^{2}}}\] \[\pi {{r}^{2}}=154={{\pi }^{2}}=\frac{154}{\pi }\,\,and\,\,r=\sqrt{\frac{154}{22/7}=7}\] \[\therefore \pi rl=\frac{22}{7}\times 7\times \sqrt{49+{{9}^{2}}}\] \[=22\times \sqrt{130}=250.8.\]
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