A) 112.5m
B) 112m
C) 212m
D) 312m
Correct Answer: B
Solution :
Volume of block \[=(4.4\times 2.6\times 1)\] \[=(440\times 260\times 100)c{{m}^{3}}\] Let \[r=\] internal radius of pipe =30 cm And \[R=\] external radius of pipe \[=(30+5)cm=35cm\] \[\therefore \]Volume of iron used \[=\pi h({{R}^{2}}-{{r}^{2}})\] \[=\pi h({{35}^{2}}-{{30}^{2}})=\pi h(325)\] Volume of iron pipe = Volume of block \[\Rightarrow 325\pi h=440\times 260\times 100\] \[\Rightarrow h=440\times 260\times 100\times \frac{7}{22}\times \frac{1}{325}\] \[\Rightarrow h=11200cm=112m\]
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