8th Class Mathematics Mensuration Question Bank Mensuration

  • question_answer
    Match the figure in column I with their total surface area in column II
    Column I Column II
    (p) (i) \[836\text{ c}{{\text{m}}^{2}}\]
    (q) (ii) \[340\text{ c}{{\text{m}}^{2}}\]
    (r) (iii) \[\text{1014 c}{{\text{m}}^{\text{2}}}\]
    (s) (iv) \[\text{1287c}{{\text{m}}^{2}}\]

    A)  P\[\to \](iii); Q\[\to \](iii); R\[\to \](iv); S\[\to \](i)

    B)  P\[\to \](ii); Q\[\to \](iv); R\[\to \](i): S\[\to \](iii)

    C)  P\[\to \](ii); Q\[\to \](iii); R\[\to \](i); S\[\to \](iv)

    D)  P\[\to \](ii):Q\[\to \](iv);R\[\to \](ii);S\[\to \](i)

    Correct Answer: B

    Solution :

    P. Total surface area \[=2(lb+bh+hl)\] \[=2(10\times 5+5\times 8+8\times 10)\] \[=2(50+40+80)=2\times 170=340c{{m}^{2}}\] Q. Total surface area \[=2\pi r(r+h)\] \[=2\times \frac{22}{7}\times \frac{21}{2}\left( \frac{21}{2}+9 \right)=1287c{{m}^{2}}\] R. We have, \[\pi {{r}^{2}}=154\] \[\Rightarrow \frac{22}{7}\times {{r}^{2}}=154\Rightarrow {{r}^{2}}=49\Rightarrow r=7cm\] \[\therefore \] Surface area \[=2\pi r(r+h)\] \[=2\times \frac{22}{7}\times 7(7+12)=836c{{m}^{2}}\] S. Let \[l\] be the edge of cube. \[\Rightarrow {{l}^{3}}=2197\Rightarrow l=13cm\] Total surface Area \[=6{{l}^{2}}=6{{(13)}^{2}}=1014c{{m}^{2}}\]


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