A) 1.01 p.c.
B) 3.03 p.c.
C) 2.01 p.c.
D) 1.2 p.c.
Correct Answer: C
Solution :
Let radius of cylinder is r and height of cylinder is h \[\therefore \] Volume of cylinder \[=\pi \,{{r}^{2}}\,h\] New radius \[=r+1%\] of \[r=r+\frac{1}{100}r=\frac{101}{100}r\] New height \[=h+1%\] of \[h=\frac{101}{100}h\] \[\therefore \] Volume of new cylinder \[=\pi \,\left( \frac{101}{100}r \right)\,\,\left( \frac{101}{100}h \right)\] \[=\frac{\pi \,\,{{(101)}^{3}}{{r}^{2}}h}{{{(100)}^{3}}}\] \[\therefore \] Increase in volume \[={{\left( \frac{101}{100} \right)}^{3}}\,{{r}^{2}}h-\pi {{r}^{2}}h\] \[=\pi (.030301)\,{{r}^{2}}h\] Hence, percentage increase \[=3.03\text{ }pc\]
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