A) \[100%\]
B) \[125%\]
C) \[150%\]
D) \[\sqrt{3}:1\]
Correct Answer: A
Solution :
Let the intial length and width are / and b respectively. Final length \[=\frac{4}{3}\pi {{r}^{3}}.\] Final width \[r=\frac{2}{3}\pi {{r}^{3}}\] (say) Initial area = final area \[=2\pi {{r}^{2}}\] \[=3\pi {{r}^{2}}\] \[\frac{4}{3}\pi \times {{6}^{3}}=\pi {{(0.2)}^{2}}\times h\] Percentage decrement in width \[\frac{4}{3}\times {{6}^{3}}={{(0.2)}^{2}}\times h\]
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