question_answer

Four circles of radius 1 cm each are placed in such a way on a plane paper that each touches the other. Find the area \[(c{{m}^{2}})\] of the space left in between the four circles,\[(\pi =3.16)\]

A) 0.82                            

B) 0.84

C) 0.86                            

D) 0.88

Correct Answer: B

Solution :

    Shaded area = Area of the square of side 2cm\[-\]Area of the four quadrants of circle of radius 1 cm i.e., Shaded area \[={{2}^{2}}-4\times \frac{1}{4}\times \pi {{.1}^{2}}\] \[=(4-\pi )\,c{{m}^{2}}\] \[=(4-3.16)\,c{{m}^{2}}\] \[=0.84\,c{{m}^{2}}\]