A) \[\sqrt{5}:2\]
B) \[2:\sqrt{5}\]
C) \[37\frac{1}{2}%\]
D) \[60%\]
Correct Answer: B
Solution :
AB = 4, BC = 10 \[1c{{m}^{2}}=100m{{m}^{2}}\] \[NC=10\,cos\,30{}^\circ =10\times \frac{\sqrt{3}}{2}=5\sqrt{3}\] \[1d{{m}^{2}}=100c{{m}^{2}}\] Area of ABCD \[1000c{{m}^{3}}=1d{{m}^{3}}\](sum of parallel sides) \[1{{m}^{2}}=100d{{m}^{2}}\] height \[1Litre=1d{{m}^{3}}=1000c{{m}^{3}}\] \[1{{m}^{2}}=10000c{{m}^{2}}\]
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