A) 3.02%
B) 3%
C) 4.5%
D) 5.7%
Correct Answer: A
Solution :
Let the initial side be a. Then final side \[=1:x\] Initial area of the triangle \[2\pi r=44\] Final area of the triangle \[r=\frac{44}{2\times \frac{22}{7}}=7m\] The percentage increase in area \[=\pi {{r}^{2}}=\frac{22}{7}\times 7\times 7=154{{m}^{2}}\] \[\frac{\pi {{d}^{2}}}{4}=2464\]
You need to login to perform this action.
You will be redirected in
3 sec
