A) 100%
B) 200%
C) 300%
D) 400%
Correct Answer: C
Solution :
Let the initial length and width be \[l\] & b respectively. Then the initial area \[{{d}^{2}}=\frac{2464}{\frac{22}{7}}=3136\]. According to the question, New length and width will be \[d=\sqrt{3136}=56m.\] and 2b respectively \[2\pi r-r=37\] New area \[r=\frac{37}{2\pi -1}=\frac{37}{2\times \frac{2}{7}-1}=7m\] Increment in area \[6cm\]
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