A) \[{{m}^{2}}\]
B) \[8070{{m}^{2}}\]
C) \[8270{{m}^{2}}\]
D) \[8370{{m}^{2}}\]
Correct Answer: B
Solution :
Let H be the height of II nd flask. Volume of II nd flask = Volume of 1st flask \[=\left( \frac{1}{2}\times BD\times AL \right)+\left( \frac{1}{2}\times BD\times CM \right)\] \[=\frac{1}{2}\times BD\times (AL+CM)\] \[=b\times h\] \[=\frac{1}{2}\times \] \[=\frac{1}{2}{{d}_{1}}\times {{d}_{2}}\]
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