A) \[16\,{{m}^{2}}\]
B) \[4\,{{m}^{2}}\]
C) \[10\,{{m}^{2}}\]
D) \[8\,{{m}^{2}}\]
Correct Answer: D
Solution :
Area of square ABCD = 16 side\[\times \]side = 16 \[\Rightarrow \] side = 4 m. \[{{E}_{1}}\,{{F}_{1}}\,G\]and\[H\]are mid-points \[\therefore \] Area of 4 triangles\[=4\left[ \frac{1}{2}\times 2\times 2 \right]\] \[=8\,{{m}^{2}}.\] Now, area of shaded Square\[=16-8=8\,{{m}^{2}}.\]
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