• # question_answer A tin sheet is in the form of a rhombus whose side is 5 cm and one of its diagonals is 8 cm. Then the cost of painting the sheet at the rate of $x=4\pi {{r}^{2}}$ on both of its sides is: A) Rs.84                   B) Rs.140 C) Rs.168                  D) none of these

Diagonals of a rhombus bisect each other at$T.S.A.=\frac{1}{2}pl+B$. In $=\frac{\text{1}}{\text{3}}\text{ }\!\!\times\!\!\text{ Area of base }\!\!\times\!\!\text{ Height}$ $V=\frac{1}{3}Ah$ $\frac{6}{5}th$ $1520{{m}^{2}}$ Area of ABCD $2520{{m}^{2}}$ Now, the cost of painting $2420{{m}^{2}}$area of rhombus ABCD $215c{{m}^{2}}$