A) 6cm
B) 12cm
C) 9cm
D) 10cm
Correct Answer: A
Solution :
Let \[{{\text{V}}_{\text{1}}}\], \[{{\text{V}}_{2}}\] and \[{{\text{V}}_{3}}\] be the volumes of the three cubes. Then\[{{V}_{1}}={{(3)}^{3}}=27\text{ }c{{m}^{3}},V={{(4)}^{3}}=64c{{m}^{3}}\] and \[{{V}_{3}}={{(5)}^{3}}=125c{{m}^{3}}\] \[\therefore \] Total volume \[=27+64+125=216\text{ }c{{m}^{3}}\] Now, volume of new cube\[=216\text{ }c{{m}^{3}}\] \[\therefore \] Its edge \[=\sqrt[3]{216}=6cm\]
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