A) 2 : 9
B) 1 : 9
C) 1 : 11
D) 2 : 13
Correct Answer: B
Solution :
(b): \[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{1}{27}=\frac{{{a}_{1}}^{3}}{{{a}_{2}}^{3}}=\frac{1}{27}\] \[\Rightarrow \frac{{{a}_{1}}}{{{a}_{2}}}=\frac{1}{3}\] (where a,, a, are sides of cubes respectively) \[\Rightarrow \frac{{{a}_{1}}^{2}}{{{a}_{2}}^{2}}=\frac{1}{9}\Rightarrow \frac{6{{a}_{1}}^{2}}{6{{a}_{2}}^{2}}=\frac{1}{9}\] or \[\frac{{{S}_{1}}}{{{S}_{2}}}=\frac{1}{9}\].
You need to login to perform this action.
You will be redirected in
3 sec
