• # question_answer An athletic track 14m wide consists of two straight sections 130m long joining semicircular ends whose inner radius in 3.5m. The area of the shaded region is: A)  $=\frac{4}{3}\pi {{r}^{3}}=\frac{4}{3}\pi \times {{\left( \frac{x}{4\pi } \right)}^{3/2}}$                B)  $=\frac{4}{3}\pi \times \frac{x}{4\pi }\sqrt{\frac{x}{4\pi }}=\frac{x}{3}\sqrt{\frac{x}{4\pi }.}$ C)  $\frac{\frac{4}{3}\pi {{r}^{3}}}{\frac{4}{3}\pi {{(21-r)}^{3}}}=\frac{64}{27}$                D) None of these

Area of shaded region $130\sqrt{2}m$ $72c{{m}^{2}}$ $12\sqrt{35}c{{m}^{2}}$