8th Class Mathematics Mensuration Question Bank Mensuration

  • question_answer
    A tent is in the form of a right circular cylinder surmounted by a cone. The diameter of cylinder is 24 m, the height of the cylindrical portion is 11 m, while the vertex of the cone is 16 m above the ground. The area of the canvas required for the tent is:

    A)  \[\Rightarrow \]               

    B)  \[\frac{r}{21-r}=\frac{4}{3}\]

    C)  \[\Rightarrow \]                      

    D)  \[3r=84-4r\]

    Correct Answer: A

    Solution :

    \[24\sqrt{35}c{{m}^{2}}\] \[150c{{m}^{2}}\]  \[30\sqrt{7}cm\] Area of the canvas = lateral surface area of cylinder + lateral surface area of cone \[\frac{15\sqrt{7}}{2}cm\] \[\frac{15\sqrt{7}}{4}cm\]    


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