• # question_answer A standard $90{}^\circ V$-notch weir is used to measure discharge. The discharge is ${{Q}_{1}}$ for a height ${{H}_{1}}$ above the sill and ${{Q}_{2}}$ is the discharge for a height ${{H}_{2}}.$If ${{\text{H}}_{\text{2}}}\text{/}{{\text{H}}_{\text{1}}}$ is 4, then ${{Q}_{\text{2}}}\text{/}{{\text{Q}}_{\text{1}}}$ is: A) 32                                B) $16\sqrt{2}$C) 16                                D) 8

$Q\propto {{H}^{3/2}},$ $\frac{{{Q}_{2}}}{{{Q}_{1}}}={{\left( \frac{{{H}_{2}}}{{{H}_{1}}} \right)}^{3/2}}={{4}^{3/2}}=8$