A) Halved
B) Kept unchanged
C) Doubled
D) made four times
Correct Answer: D
Solution :
Surface finish \[{{({{R}_{a}})}_{\max }}\frac{{{f}^{2}}}{8r}\] \[\frac{{{r}^{2}}}{{{r}^{1}}}={{\left( \frac{{{f}_{2}}}{{{f}_{1}}} \right)}^{2}}={{2}^{2}}=4\]
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