• # question_answer Given that cutting speed = 9 m/min, the return time to cutting time ratio is = 1 : 2 to the feed rate = 0.3 mm/stroke, the clearance at each of cut = 25 mm and that the plate is fixed 700 mm side along the direction of tool travel, the time required for finishing one flat surface of a plate of size $700\times 300\,\,mm$ in a shaper, will be: A) 10 min             B) 12.5 minC) 15 min             D) 20 min

Solution :

Number of strokes, $n=\frac{Length\,\,of\,\,stroke}{Feed\,\,rate}$ $=\frac{30}{0.3}=100$ Length of cut, $L=700+2\times 25=750\,\,mm$ Cutting time $=\frac{L\times n\times 1.5}{{{v}_{c}}}$ $=\frac{0.75\times 100\times 1.5}{9}$  $=12.5\text{ }min$

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