• # question_answer A stepped cylindrical container is filled with a liquid as shown in the given figure. The container with its axis vertical, is first placed with its larger diameter downward and then upward. The ratio of the forces at the bottom in the two cases will be: A) $\frac{1}{2}$                          B) 1C) 2                                 D) 4

$F=\rho gAh$ Or $F\propto Ah$ For same, h, $F\propto A$ $\frac{{{F}_{2}}}{{{F}_{1}}}=\frac{{{A}_{2}}}{{{A}_{1}}}={{\left( \frac{2d}{d} \right)}^{2}}=4$