A) 10.14 m of water absolute
B) 0.2 m of water
C) 1.2 of water vacuum
D) 4901 Pa
Correct Answer: D
Solution :
Neglecting static head due to air, \[{{P}_{A}}=\rho g{{h}_{w}}={{10}^{3}}\times 9.81\times 500\times {{10}^{-\,3}}\] =4905 Pa = 4901 PaYou need to login to perform this action.
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