| (i) \[_{12}^{24}X\] | (ii) \[_{9}^{19}X\] |
| (iii) \[_{15}^{31}X\] | (iv) \[_{11}^{23}X\] |
A) (i) and (ii) only
B) (ii) and (iii) only
C) (i) and (iv) only
D) (ii) and (iv) only
Correct Answer: C
Solution :
\[_{12}^{24}X\]is \[Mg._{9}^{19}X\] is \[F,_{15}^{31}X\] is P and \[_{11}^{23}X\] is Mg and Na are metals while F and P are non- metals.
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