| Observe the given figure carefully. |
|
| The residue left behind in the crucible, substance Y and the substance which can replace Y in the above process are respectively |
A) White powder of Pb, Cu and K
B) Brown crystals of \[P{{b}_{2}}{{O}_{3}},\,C\] and CO
C) Shiny globules of Pb, C and Mg
D) Black mass of \[P{{b}_{2}}{{O}_{3}},\,CO\] and Cu.
Correct Answer: C
Solution :
\[2PbO+\underset{(Y)}{\mathop{C}}\,\xrightarrow{{}}\underset{(Shiny\,globules)}{\mathop{2Pb+C{{O}_{2}}}}\,\] Mg can also be used as the reducing agent in this process.
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