A) 1.8
B) 48.4
C) 9.18
D) 94.6
Correct Answer: C
Solution :
The density of solution \[=1.8\,gm/ml\] Weight of one litre of solution \[=1800\,gm\] \[\therefore \] Weight of \[{{H}_{2}}S{{O}_{4}}\] in the solution\[=\frac{1800\times 90}{100}\]=162gm \[\therefore \] Weight of solvent \[=1800-1620=180\,gm\] \[\therefore \] Molality \[=\frac{1620}{98}\times \frac{100}{180}=9.18\]You need to login to perform this action.
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