• # question_answer A fit is specified as $215\,\,H\,\,8/e8.$The tolerance value for a nominal diameter of 25 mm in IT8 is 33 microns and fundamental deviation for the shaft is $-\,40$ microns. The maximum clearance of the fit in micron is: A) $-\,7$                          B) 7C) 73                                D) 106

Minimum clearance of fit $=33+40+33=106$microns