question_answer

Three blocks \[{{B}_{1}},\] \[{{B}_{2}}\] and \[{{B}_{3}}\] are to inserted in cannel of width S maintaining a minimum gap of width \[T=0.125\,\,m,\] as shown in figure. For \[=\,18.75\pm 0.08\,;\,Q=25.00\pm 0.12\,;\,R=28.125\pm 0.1\]and \[S=72.35+X,\] (where all dimensions are in mm), the tolerance X is:

A) \[+0.38\]                      

B) \[-\,0.38\]

C) \[+0.05\]                      

D) \[-\,0.05\]