A) 98 cm
B) 100 cm
C) 150 cm
D) 200 cm
Correct Answer: A
Solution :
\[m=\frac{{{f}_{o}}}{{{f}_{e}}}\] Þ \[\frac{100}{{{f}_{e}}}=50\] Þ \[{{f}_{e}}=2\,cm\] Normal distance \[{{f}_{o}}-{{f}_{e}}=100-2=98\,cm.\]You need to login to perform this action.
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