JEE Main & Advanced Physics Ray Optics Question Bank Microscope and Telescope

  • question_answer
    Magnification of a compound microscope is 30. Focal length of eye-piece is 5 cm and the image is formed at a distance of distinct vision of 25 cm. The magnification of the objective lens is                                              [DPMT 2005]

    A)            6    

    B)            5

    C)            7.5 

    D)            10

    Correct Answer: B

    Solution :

                       \[m=\frac{{{v}_{o}}}{{{u}_{o}}}\left( 1+\frac{D}{{{f}_{e}}} \right)={{m}_{o}}\left( 1+\frac{D}{{{f}_{e}}} \right)\]                    Þ \[30={{m}_{o}}\left( 1+\frac{25}{5} \right)={{m}_{0}}\times 6\]         Þ \[{{m}_{o}}=5\].


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