A) 10o
B) 24o
C) 50o
D) 1/6o
Correct Answer: B
Solution :
Since \[m=\frac{{{f}_{o}}}{{{f}_{e}}}\] Also \[m=\frac{Angle\ subtended\ by\ the\ image}{Angle\ subtended\ by\ the\ object}\] \[\therefore \frac{{{f}_{o}}}{{{f}_{e}}}=\frac{\alpha }{\beta }\]\[\Rightarrow \alpha =\frac{{{f}_{o}}\times \beta }{{{f}_{e}}}=\frac{60\times 2}{5}={{24}^{o}}\]
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