JEE Main & Advanced Physics Ray Optics Question Bank Microscope and Telescope

  • question_answer
    The diameter of the objective of the telescope is 0.1 metre and wavelength of light is 6000 Å. Its resolving power would be approximately                                                             [MP PET 1997]

    A)            \[7.32\times {{10}^{-6}}rad\]                                            

    B)            \[1.36\times {{10}^{6}}rad\] 

    C)            \[7.32\times {{10}^{-5}}rad\]                                            

    D)            \[1.36\times {{10}^{5}}rad\] 

    Correct Answer: D

    Solution :

                       Resolving power \[=\frac{d}{1.22\ \lambda }=\frac{0.1}{1.22\times 6000\times {{10}^{-10}}}\]            \[\cong 1.36\times {{10}^{5}}radian\]


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