A) 1.8 cm
B) 1.5 cm
C) 2.1 cm
D) 2.4 cm
Correct Answer: A
Solution :
\[{{L}_{\infty }}={{v}_{o}}+{{f}_{e}}\]\[\Rightarrow 14={{v}_{o}}+5\]\[\Rightarrow {{v}_{o}}=9\ cm\] Magnifying power of microscope for relaxed eye \[m=\frac{{{v}_{o}}}{{{u}_{o}}}.\frac{D}{{{f}_{e}}}\] or \[25=\frac{9}{{{u}_{o}}}.\frac{25}{5}\] or \[{{u}_{o}}=\frac{9}{5}=1.8\ cm\]
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