question_answer

The diameter of the objective of a telescope is a,  its magnifying power is m and wavelength of light is \[\lambda .\]The resolving power of the telescope is                                                         [MP PMT 2000]

A)            \[(1.22\,\lambda )/a\]     

B)            \[(1.22\,a)/\lambda \]

C)            \[\lambda m/(1.22a)\]     

D)            \[a/(1.22\lambda \,)\]