A) 80 : 20
B) 90 : 10
C) 91 : 9
D) 81 : 19
Correct Answer: D
Solution :
[d] Here, a = 10 L, n = 2 and x = 100 L \[\therefore \] Quantity of wine in end \[=x{{\left( 1-\frac{a}{x} \right)}^{n}}=100{{\left( 1-\frac{10}{100} \right)}^{2}}=81\,\text{L}\] \[\therefore \] Required ratio \[=81:(100-81)=81:19\] |
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