A) Ethylethanal
B) 2-Butanone
C) Propanal
D) Propanone
Correct Answer: B
Solution :
[b] \[HC\equiv CH\xrightarrow{HgS{{O}_{4}}/{{H}^{+}}}\underset{(P)}{\mathop{C{{H}_{3}}CHO}}\,\xrightarrow{[o]}\]You need to login to perform this action.
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