A) a - b
B) a+b
C) \[\sqrt{{{a}^{2}}+{{b}^{2}}}\]
D) \[\sqrt{{{a}^{2}}-{{b}^{2}}}\]
Correct Answer: A
Solution :
[a] This distance of the origin form any point (x, y) on the curve is \[\sqrt{{{x}^{2}}+{{y}^{2}}}=\sqrt{{{a}^{2}}+{{b}^{2}}-2ab\cos \left( t-\frac{at}{b} \right)}\] \[\le \sqrt{{{a}^{2}}+{{b}^{2}}+2ab}\] \[[\therefore minimum\,\,cos\left( t-\frac{at}{b} \right)=-1]\] \[=a+b\]
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