\[{{E}_{H-H}}=104.2\,kcal\,mo{{l}^{-1}}\] |
\[{{E}_{F-F}}=36.6\,kcal\,mo{{l}^{-1}}\] |
\[{{E}_{H-F}}=134.6\,kcal\,mo{{l}^{-1}}\] |
\[{{X}_{H}}=2.1\] |
Answer:
4
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