JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Mock Test - Complex Numbers and Quadratic Equations

  • question_answer
    If p and q are the roots of the equation \[{{x}^{2}}+px+q=0\], then

    A) p =1, q=-2      

    B) p =0, q=2

    C) p =-2, q=0      

    D) p =-2, q=1

    Correct Answer: A

    Solution :

    [a] \[p+q=-p\]and \[pq=q\]gives \[q(p-1)=0\Rightarrow q=0or\,p=1\] If q=0, then p=0, i.e., p=q Therefore, p=1 and q=-2.


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