A) \[\frac{\rho {{L}^{3}}}{8{{\pi }^{2}}}\]
B) \[\frac{\rho {{L}^{3}}}{16{{\pi }^{2}}}\]
C) \[\frac{5\rho {{L}^{3}}}{8{{\pi }^{2}}}\]
D) \[\frac{3\rho {{L}^{3}}}{8{{\pi }^{2}}}\]
Correct Answer: D
Solution :
[d] \[L=2\pi r\Rightarrow r=\frac{L}{2\pi },m=\rho L\] \[{{l}_{xy}}=\frac{3}{2}m{{r}^{2}}\] \[=\frac{3}{2}\rho L{{\left( \frac{L}{2\pi } \right)}^{2}}=\frac{3}{8}\frac{\rho {{L}^{3}}}{{{\pi }^{2}}}\]You need to login to perform this action.
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