A) 1.08 g
B) 10.8 g
C) 21.6 g
D) 108 g
Correct Answer: B
Solution :
[b] When 96500 coulombs of electricity is passed through the electroplating bath amount of Ag deposited \[=108g.\] \[\therefore \]When 9650 coulombs of electricity is passed, deposited Ag \[=\frac{108}{96500}\times 9650=10.8g\]You need to login to perform this action.
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