A) \[1.52\times {{10}^{-8}}Wb/{{m}^{2}}\]
B) \[1.52\times {{10}^{-7}}Wb/{{m}^{2}}\]
C) \[1.6\times {{10}^{-6}}Wb/{{m}^{2}}\]
D) \[1.6\times {{10}^{-7}}Wb/{{m}^{2}}\]
Correct Answer: C
Solution :
[c] \[c=\frac{{{E}_{0}}}{{{B}_{0}}}\] \[\therefore {{B}_{0}}=\frac{{{E}_{0}}}{c}=1.6\times {{10}^{-6}}Wb/{{m}^{2}}\]You need to login to perform this action.
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