A) -4.2V
B) -9.4V
C) -17.8V
D) +9.4 V
Correct Answer: B
Solution :
[b] \[E={{W}_{0}}+e{{V}_{0}}\] For hydrogen atom, \[E=+13.6eV\] \[\therefore +13.6=4.2+e{{V}_{0}}\] \[\Rightarrow {{V}_{0}}=\frac{(13.6-4.2)eV}{e}=9.4V\] Potential at anode\[=-9.4V\]You need to login to perform this action.
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