A) \[1490,\,1510\]
B) \[1510,\,1490\]
C) \[\frac{1}{1490},\frac{1}{1510}\]
D) \[\frac{1}{1590},\frac{1}{1490}\]
Correct Answer: A
Solution :
[a] Here, \[{{f}_{c}}=1.5MHz=1500kHz,{{f}_{m}}=10kHz\] \[\therefore \] Low side band frequency \[={{f}_{c}}-{{f}_{m}}=1500kHz-10kHz=1490kHz\]Upper side band frequency \[={{f}_{c}}+{{f}_{m}}=1500kHz+10kHz=1510kHz\]You need to login to perform this action.
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