A) \[E/R\]
B) \[E/2R\]
C) \[2E/3R\]
D) Zero
Correct Answer: A
Solution :
[a] Diodes \[{{D}_{1}}\]and \[{{D}_{3}}\] are forward biased and \[{{D}_{2}}\] is reverse biased so the circuit can be redrawn as follows. \[\Rightarrow i=\frac{E}{R}\]You need to login to perform this action.
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