JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Mock Test - Integrals

  • question_answer
    Let \[f(0)=0\] and \[\int\limits_{0}^{2}{f'(2t){{e}^{f(2t)}}dt=5}\]. Then the value of f(4) is

    A) log 2                

    B) log 7

    C) log 11   

    D) log 13

    Correct Answer: C

    Solution :

    [c] We have \[\int\limits_{0}^{2}{f'(2t){{e}^{f(2t)}}dt=5}\] Put \[{{e}^{f(2t)}}=y\] \[\therefore 2f'(2t){{e}^{f(2t)}}dt=dy\] \[\therefore \frac{1}{2}\int\limits_{{{e}^{f(0)}}}^{{{e}^{f(4)}}}{dy=5}\] Or \[\int\limits_{{{e}^{f(0)}}}^{{{e}^{f(4)}}}{dy=10}\] Or \[{{e}^{f(4)}}-{{e}^{f(0)}}=10\] Or \[{{e}^{f(4)}}=10+1=11\] Or \[f(4)=log11\]


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