JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Mock Test - Integrals

  • question_answer
    The value of \[\int\limits_{1}^{e}{\frac{1+{{x}^{2}}\ln \,x}{x+{{x}^{2}}\ln \,x}dx}\]is

    A) \[e\]                  

    B) \[\ln \,(1+e)\]

    C) \[e+\ln (1+e)\]  

    D) \[e-\ln (1+e)\]

    Correct Answer: D

    Solution :

    [d] \[I=\int\limits_{1}^{e}{\left( \frac{1}{x}+1 \right)}dx-\int\limits_{1}^{e}{\frac{1+\ln x}{1+x\ln x}dx}\] \[={{[\ln x+x]}_{1}}^{e}-[\ln (1+x\ln x)]_{1}^{e}\] \[=e-\ln (1+e)\]


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