A) \[3\pi /2\]
B) \[\pi \]
C) \[3\pi /4\]
D) \[2\pi \]
Correct Answer: A
Solution :
[a] From the given relation \[\cos \theta =(2sin\theta cos\theta )sin\theta ,sin\theta \ne 0\] Or \[\sin \theta =\pm \frac{1}{\sqrt{2}}\,or\,\cos \theta =0\] Or \[\theta =\frac{\pi }{4},\frac{3\pi }{4},\frac{\pi }{2}\] \[(\because \theta \in [0,\pi ])\] Then the sum of roots is \[3\pi /2\].
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