A) 3
B) 4
C) 5
D) 6
Correct Answer: A
Solution :
[a] \[6\cos 2\theta +2{{\cos }^{2}}(\theta /2)2si{{n}^{2}}\theta =0\] Or \[12{{\cos }^{2}}\theta -6+1+\cos \theta +2-2{{\cos }^{2}}\theta =0\] or \[10{{\cos }^{2}}\theta +\cos gq-3=0\] or \[(5cos\theta +3)(2cos\theta -1)=0\] or \[\cos \theta =-\frac{3}{5},\frac{1}{2}\] \[\Rightarrow \theta =\frac{\pi }{3};\pi -{{\cos }^{-1}}\left( \frac{3}{5} \right),-\frac{\pi }{3},-\pi +{{\cos }^{-1}}\left( \frac{3}{5} \right)\]
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